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Mencoba jawab dengan rumuz praktizz...
Pada jam 08.00 si A udah menempuh 40 Km.
Jarak sisa =120-40=80 Km
Jumlah kecepatan = 20+40 =60 km/jam
lama menyongsong =80/60 x 1 Jam = 1,33 = 1 jam 19,8 menit
Jadi bertemu jam 08:00 + 1 jam 20 menit = pk 09:20
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waduh. ketemu matematika lagi
I'm no Magiciant, but I'm RailFans...
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Aduh... Bukan bidang saya ini (matematika)...
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hag hag...dho mlayu kabeh ki piye....kasih soal baru kang....
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14-06-2010, 11:34 AM
(This post was last modified: 14-06-2010, 11:35 AM by Ryzky_Widi.)
Nih saya beri tebakan no 48...
Ada 2 KA berjalan masing-masing berlawanan arah dan saling mendekat dalam jarak sekitar 500 m (1 Jalur). Nah, pertanyaannya, bagaimana caranya agar 2 KA itu tidak bertabrakan atau PLH...? (Jawaban = Berhenti = SALAH, KA harus jalan terus...)
Ayo... coba dipikir...
- R y z k y W i d i A T m a j a -